(defun abs (x) (if (< x 0) (- x) x))
Write a new version of the absolute-value function called
new-abs, that produces equivalent values but uses
>(setf formula '(sqrt (/ (+ (expt x 2) (expt y 2)) 2))) >(presentp 'x formula) T >(presentp 'z formula) NIL
> (setf x (cons (list 1 2) (list 3 4))) ((1 2) 3 4) >(fringe x) (1 2 3 4) >(fringe (list x x)) (1 2 3 4 1 2 3 4)